Difference between revisions of "Advanced Tutorial Lesson 3: Investigating Audio Power Amplifiers"
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|All versions|{{download|http://www.emagtech.com/downloads/ProjectRepo/AnalogLesson16.zip Analog Lesson 16}} }} | |All versions|{{download|http://www.emagtech.com/downloads/ProjectRepo/AnalogLesson16.zip Analog Lesson 16}} }} | ||
− | + | == What You Will Learn == | |
In this tutorial you will build and test common emitter and class AB amplifiers and compare their power efficiencies. Since small-signal approximation does not hold well for power amplifiers, you will use RF.Spice's Transient Test to analyze these nonlinear circuits. | In this tutorial you will build and test common emitter and class AB amplifiers and compare their power efficiencies. Since small-signal approximation does not hold well for power amplifiers, you will use RF.Spice's Transient Test to analyze these nonlinear circuits. |
Latest revision as of 18:02, 8 November 2016
Contents
What You Will Learn
In this tutorial you will build and test common emitter and class AB amplifiers and compare their power efficiencies. Since small-signal approximation does not hold well for power amplifiers, you will use RF.Spice's Transient Test to analyze these nonlinear circuits.
Exploring a Basic Common-Emitter Amplifier
The following is a list of parts needed for this part of the tutorial lesson:
Part Name | Part Type | Part Value |
---|---|---|
VCC | Voltage Source | DC, 15 |
VS | Voltage Source | Waveform TBD |
R1 | Resistor | 66k |
R2 | Resistor | 6k |
R3 | Resistor | 10k |
R4 | Resistor | 900 |
RL | Resistor | 10k |
C1 - C2 | Capacitor | 1u |
C3 | Capacitor | 220n |
Q1 | Q2N3904 NPN BJT | Defaults |
Am1 | Ammeter | N/A |
IN, OUT | Voltage Probe Marker | N/A |
Place and connect the parts of the basic common emitter amplifier as shown in the figure below:
Set the waveform of the voltage source VS according to the following table:
Offset Voltage | 0 |
---|---|
Peak Amplitude | 100mV |
Frequency | 1kHz |
Delay Time | 0 |
Damping Factor | 0 |
First, run a DC Bias Test of your amplifier to find the operating point parameters of Q1. You will find ICQ = 755μA. Therefore, the small-signal transconductance of the transistor is gm = ICQ / VT = 0.029S. Run a Transient Test of this circuit with the parameters specified below:
Start Time | 5m |
---|---|
Stop Time | 10m |
Linearize Step | 10u |
Step Ceiling | 1u |
Preset Graph Plots | v(in), v(out), i(rl), p(vcc), p(rl) |
Note that the start time of the transient test in this tutorial is t = 5ms. Before you start to sample the waveforms, you need to let the transients settle down. The simulation results are shown in the figure below. Note that the five plots involve voltages, currents and powers with entirely different ranges and scales. Therefore, you need to use the "Zoom to Selected Plot" feature of the graph window to better view the details of each plot.
In the above figure, p(vcc) is the DC power of the DC power supply VCC, while p(rl) is the power delivered to the load. The ratio p(rl)/p(vcc) defines the power efficiency of the amplifier. From the above plots, you can read the peak-to-peak input and output voltages, voltage gain and power efficiency:
RL | Vin(p-p) | Vout(p-p) | Voltage Gain | IRL(p-p) | PVCC | PRL | Power Efficiency |
---|---|---|---|---|---|---|---|
10kΩ | 1686mV | 200mV | 8.43 | 168.5μA | 15.68mW | 71.28μW | 0.46% |
Observing the Effect of Low Load Resistance
Audio power amplifiers are usually used to drive very small loads. Change the value of RL to 100Ω, and run the transient test once again. The results for a 100Ω load are shown ion the figure and summarized below.
RL | Vin(p-p) | Vout(p-p) | Voltage Gain | IRL(p-p) | PVCC | PRL | Power Efficiency |
---|---|---|---|---|---|---|---|
100Ω | 34mV | 200mV | 0.17 | 167.4μA | 14.46mW | 2.8μW | 0.02% |
You can see that the peak-to-peak output voltage has dropped drastically to 34mV. This is obviously expected since the 100Ω load shunts the collector resistor R3 and reduces the voltage gain: GV = -RC,tot / RE,tot.
Finally, let's increase the input signal level from 100mV to 1V (2Vp-p) to see how the output is affected. The figure below shows the results:
You can see that the load current has increased significantly to more than 1mA but at the expense of output voltage distortion. You may conclude that the common emitter amplifier is not an effective solution when the load is small.
Building and Testing a Class AB BJT Amplifier
The following is a list of parts needed for this part of the tutorial lesson:
Part Name | Part Type | Part Value |
---|---|---|
VCC | Voltage Source | DC, 15 |
VS | Voltage Source | Waveform TBD |
R1 | Resistor | 1k |
R2 | Resistor | 12k |
R3 | Resistor | 1k |
R4 | Resistor | 100 |
R5 - R6 | Resistor | 0.33 |
RL | Resistor | 100 |
C1 - C2 | Capacitor | 10u |
D1 - D2 | 1N4148 Diode | Defaults |
Q1 - Q2 | Q2N3904 NPN BJT | Defaults |
Q3 | Q2N3906 PNP BJT | Defaults |
Am1 | Ammeter | N/A |
IN, OUT | Voltage Probe Marker | N/A |
Place and connect the part of the class AB BJT amplifier as shown figure below. The transistor Q1 acts as the driver amplifier. The complementary NPN-PNP pair Q2 and Q3 form the class AB amplifier, and the diodes D1 and D2 are used to bias them.
Set the waveform of the voltage source VS according to the following table:
Offset Voltage | 0 |
---|---|
Peak Amplitude | 500mV |
Frequency | 1kHz |
Delay Time | 0 |
Damping Factor | 0 |
First, run a DC Bias Test of your amplifier to find the operating point parameters of the three transistors. The results are given below. As you would expect, the collector currents of Q2 and Q3 are almost equal in magnitude and have opposite signs.
ICQ1 | ICQ2 | ICQ3 |
---|---|---|
4.371mA | 9.995mA | -9.983mA |
Run a Transient Test of this circuit with the parameters specified below:
Start Time | 5m |
---|---|
Stop Time | 10m |
Linearize Step | 10u |
Step Ceiling | 1u |
Preset Graph Plots | v(in), v(out), i(rl), p(vcc), p(rl) |
The results are shown in the figures below and summarized in the accompanying table. Note that the peak-to-peak output voltage is 7.36V without any serious distortion. The load peak-to-peak current is 73mA. In particular, the power efficiency is more than 23%, a significant improvement over the common emitter amplifier of the previous part.
RL | Vin(p-p) | Vout(p-p) | Voltage Gain | IRL(p-p) | PVCC | PRL | Power Efficiency |
---|---|---|---|---|---|---|---|
100Ω | 1000mV | 7356mV | 7.36 | 73mA | 590mW | 138mW | 23.4% |
Similar to the previous part of this lesson, next increase the input signal level to 1V (2Vp-p) and run a new transient test with the same parameters. This time, both the output voltage and current are highly distorted as shown in the figures below:
Distortion Analysis of the Class AB Amplifier
In Tutorial Lessons 13 and 14, you performer a "Fourier Analysis" of your circuit to characterize the spectral contents of signals. RF.Spice A/D also provides a convenient virtual instrument called Distortion Meter for this purpose. The distortion meter is particularly useful for the study of power amplifiers. To initiate a distortion meter, click the Add Meter button at the top of the "Virtual Instrument Panel" at the right side of the screen. From the drop-down menu, select Distortion Meter. Click the Setup button to open the property dialog of the instrument. It has three tabs. In the first tab labeled "Test Setup" set the circuits nodes 1 and 13 for input and output, respectively. Set the Test Frequency to 1kHz and Signal Amplitude to 0.5V, which is the peak amplitude of your source signal. Press the Go button. A harmonic analysis is performed, and the results are shown in the small black display of the instrument. A Total Harmonic Distortion (THD) of 3.22% is reported on the panel.
You can see from the bar chart that your class AB BJT amplifier only has a third harmonic component at VS = 0.5V. In the second tab of the panel, you can select individual harmonics and measure their distortion as given in the table below:
2nd Harmonic Distortion | 3rd Harmonic Distortion | 4th Harmonic Distortion | 5th Harmonic Distortion | Total Harmonic Distortion (THD) |
---|---|---|---|---|
0.537% | 3.11% | 0.62% | 0.128% | 3.22% |
Exploring the Use of Darlington Pairs
The following is a list of the additional parts needed for this part of the tutorial lesson:
Part Name | Part Type | Part Value |
---|---|---|
X1 | TIP141 NPN Darlington BJT Pair | Defaults |
X2 | TIP147 PNP Darlington BJT Pair | Defaults |
In this part of the tutorial lesson, you will replace the complementary BJT pair Q2 and Q3 with complementary NPN and PNP Darlington pairs. The NPN X1 pair will replace Q2 and the PNP X2 pair will replace Q3 in the circuit of the previous part. Everything else will remain the same.
Set the waveform of the voltage source VS according to the following table:
Offset Voltage | 0 |
---|---|
Peak Amplitude | 500mV |
Frequency | 1kHz |
Delay Time | 0 |
Damping Factor | 0 |
First, run a DC Bias Test of your amplifier to find the operating point parameters of all the transistors. The results are given below. Note that the DC currents passing through resistors R6 and R7 are the same as the emitter currents of the Darlington pairs.
ICQ1 | IR6 | IR7 |
---|---|---|
4.366mA | 31.756mA | 31.756mA |
Run a Transient Test of this circuit with the parameters specified below:
Start Time | 5m |
---|---|
Stop Time | 10m |
Linearize Step | 10u |
Step Ceiling | 1u |
Preset Graph Plots | v(in), v(out), i(rl), p(vcc), p(rl) |
The results are shown in the figure and table below. You can see that both the load voltage and load current have increased in this case, which means a higher load power. In fact, the power delivered to the 100Ω load has increased by almost 50% over the previous case to more than 200mW. However, the power efficiency of the power amplifier has dropped to below 10%.
RL | Vin(p-p) | Vout(p-p) | Voltage Gain | IRL(p-p) | PVCC | PRL | Power Efficiency |
---|---|---|---|---|---|---|---|
100Ω | 1000mV | 8.6V | 8.6 | 86mA | 2.346W | 205mW | 8.7% |
In the last part of this tutorial lesson, let's measure the distortion performance of your Darlington pair class AB amplifier. Follow the same procedure described above. The results are shown in the figures below:
Note that your Darlington pairs have introduced a significant second harmonic distortion, while the third harmonic distortion has decreased by half.
2nd Harmonic Distortion | 3rd Harmonic Distortion | 4th Harmonic Distortion | 5th Harmonic Distortion | Total Harmonic Distortion (THD) |
---|---|---|---|---|
5.2% | 1.74% | 0.454% | 0.22% | 5.51% |